x+3^2=x-3(x-3+16)

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Solution for x+3^2=x-3(x-3+16) equation: 



x+3^2=x-3(x-3+16)

We move all terms to the left:

x+3^2-(x-3(x-3+16))=0

We add all the numbers together, and all the variables

x-(x-3(x+13))+3^2=0

We add all the numbers together, and all the variables

x-(x-3(x+13))+9=0



We calculate terms in parentheses: -(x-3(x+13)), so:

x-3(x+13)

We multiply parentheses

x-3x-39

We add all the numbers together, and all the variables

-2x-39

Back to the equation:

-(-2x-39)



We get rid of parentheses

x+2x+39+9=0

We add all the numbers together, and all the variables

3x+48=0

We move all terms containing x to the left, all other terms to the right

3x=-48

x=-48/3

x=-16

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